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Proof step 2 from proof psh-09 (previous step)

⊦ m -1 < n ↔ m < n +1, m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
⊦ m -1 < n ↔ ¬ n < m, m = 0

Rule argument

Additional information

Used simplifier rules: succ: ⊦ m +1 = m + 1;%s-04: ⊦ m < n + 1 ↔ ¬ n < m;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;