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Proof step 5 from proof q (previous step)

n0 = 1 ∨ m +1 +1 = n0 ⊦ n0 = 0, ∃ m0. m0 +1 = n0

Heuristic cut applied rule cut formula

And closed the goal!

Rule argument

fma: n0 = 1

Additional information

Used simplifier rules: numeral-1: m ≠ 0 ⊦ n +1 = (* m) ↔ n = m -1;%disj: ⊦ 0 ≠ n +1;%numeral-1: m ≠ 0 ⊦ n +1 = (* m) ↔ n = m -1;%inj: ⊦ n +1 = n0 +1 ↔ n = n0; Used formulas: n0 = 1