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Proof step 2 from proof rec (previous step)

∀ m. m +1 + n0 = (m + n0)+1 ⊦ m +1 + n0 +1 = (m + n0 +1)+1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
∀ m. m +1 + n0 = (m + n0)+1 ⊦ m +1 + n0 = (m + n0)+1

Rule argument

Additional information

Used simplifier rules: add-rec: ⊦ m + n +1 = (m + n)+1;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%inj: ⊦ n +1 = n0 +1 ↔ n = n0;