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Proof step 3 from proof three (previous step)

m + n = 3 ⊦ m = 0, m = 1, n = 0, m = 2 ∧ n = 1

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: m

Additional information

Used simplifier rules: gen: ⊦ ;%rec: ⊦ m +1 + n = (m + n)+1;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%numeral-1: m ≠ 0 ⊦ n +1 = (* m) ↔ n = m -1;%disj: ⊦ 0 ≠ n +1;%two-01: ⊦ m ≠ 0 ∧ n ≠ 0 → (m + n = 2 ↔ m = 1 ∧ n = 1);