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Proof step 4 from proof tot (previous step)

∀ m. n0 = m ∨ m < n0 ∨ n0 < m ⊦ n0 +1 = m, n0 +1 < m, m < n0 +1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 5:
∀ m. n0 = m ∨ m < n0 ∨ n0 < m ⊦ n0 +1 = m, m = n0, n0 +1 < m, m < n0

Rule argument

Additional information

Used simplifier rules: less-2: ⊦ n0 < n +1 ↔ n0 = n ∨ n0 < n;