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Proof step 7 from proof tot (previous step)

n0 < m, ∀ m. n0 = m ∨ m < n0 ∨ n0 < m ⊦ n0 +1 = m, m = 0, n0 +1 < m

User applied rule constructor cut

And closed the goal!

Rule argument

var: m

Additional information

Used simplifier rules: gen: ⊦ ;%disj: ⊦ 0 ≠ n +1;%inj: ⊦ n +1 = n0 +1 ↔ n = n0;%neq: ⊦ m ≠ n → (m < n +1 ↔ m < n);%lrec: ⊦ m +1 < n +1 ↔ m < n;