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Proof step 3 from proof twols (previous step)

m < n, m + n < 2 ⊦ n = 0, m = 0 ∧ n = 1

Heuristic structural induction applied rule structural induction

And closed the goal!

Rule argument

term: n

Additional information

Used simplifier rules: gen: ⊦ ;%disj: ⊦ 0 ≠ n +1;%less-2: ⊦ n0 < n +1 ↔ n0 = n ∨ n0 < n;%rec: ⊦ m +1 + n = (m + n)+1;%a: ⊦ (m + n0) + n1 = m + n0 + n1;%c: ⊦ m + n = n + m;%numeral-2: m ≠ 0 ⊦ n +1 < (* m) ↔ n < m -1;%one-01: ⊦ m < 1 ↔ m = 0;%z-01: ⊦ m + n = 0 ↔ m = 0 ∧ n = 0;%numeral-1: m ≠ 0 ⊦ n +1 = (* m) ↔ n = m -1;