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Proof step 3 from proof add (previous step)

⊦ (n0 + n) / n = n0 / n + 1, n = 0

User applied rule cut formula

And closed the goal!

Rule argument

fma: (n0 + n) / n < n0 / n + 1

Additional information

Used simplifier rules: le-01: n ≠ 0 ⊦ ¬ (n0 + n) / n ≤ n0 / n;%ls-02: n ≠ 0 ⊦ m / n < m0 / n → m < m0;%ls-03: n ≠ 0 ⊦ ¬ n0 / n + 1 < (n0 + n) / n;% ⊦ m < n + 1 ↔ ¬ n < m; (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%succ-03: ⊦ m < n ∧ m + 1 ≠ n → m + 1 < n; (forward) from specification nat-basic% ⊦ m < n → n ≠ 0; (s)% ⊦ m < m + n ↔ n ≠ 0; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss) Used formulas: (n0 + n) / n < n0 / n + 1