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Proof step 3 from proof cond-01 (previous step)

m < m / n * n ⊦ m / n = 0, n = 0

User applied rule insert lemma

And obtained the following new goals

Rule argument

spec: <toplevel> name: cond seq: n ≠ 0 ⊦ m / n * n ≤ m subst: [n, m] → [n, m]

Additional information

Used simplifier rules: ⊦ m < n → (n ≤ m ↔ false); (s) Used terms: n, m