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Proof step 7 from proof div-two-mult (previous step)

(m0 + 1) % 2 = 1 ⊦ 2 * (m0 + 1) / 2 = m0, 2 ≠ 0 ∧ (m0 + 1) % 2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
(m0 + 1) % 2 = 1, m0 % 2 = 0 ⊦ 2 * (m0 + 1) / 2 = m0

Rule argument

Additional information

Used simplifier rules: mod2-succ: ⊦ (m + 1) % 2 = 0 ↔ m % 2 ≠ 0;%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic