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Proof step 7 from proof le-div-to-mult (previous step)

n0 < m0, n * m0 ≤ m1 * m0 + n0 ⊦ n ≤ m1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 8:
m1 < n, n0 < m0, n * m0 ≤ m1 * m0 + n0 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≤ n ↔ ¬ n < m; (ss)