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Proof step 5 from proof mod-eq-01 (previous step)

m = m1 * n + n0, m0 < n, n0 < n ⊦ (m + m0) % n = m0 ↔ n0 = 0, n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
n0 < n, m0 < n ⊦ ((m1 * n + n0) + m0) % n = m0 ↔ n0 = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)