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Proof step 3 from proof mod-one-01 (
previous step
)
⊦ 1 % n = 1, n = 0, n = 1
User applied rule insert rewrite lemma
And obtained the following new goals
Proof step 4
:
⊦ m < n → m % n = m
Rule argument
spec: <toplevel> name: mod-eq seq: ⊦ m < n → m % n = m subst: [n, m] → [n, 1] flags: <all paths>
Additional information
Used simplifier rules: ⊦ m ≠ 0 → (1 < m ↔ m ≠ 1); (ss) Used terms: n, 1