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Proof step 2 from proof mod-succ-03 (previous step)

⊦ (n + 1) % n = 1, 1 = n, n = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: mod-once: n ≠ 0 ⊦ (m + n) % n = m % n;%mod-one-01: ⊦ n ≠ 0 ∧ n ≠ 1 → 1 % n = 1;%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic