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Proof step 2 from proof mod-succ-05 (previous step)

m0 < (m + 1) % n, m % n < m0 ⊦ n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m % n < (m + 1) % n, m0 < (m + 1) % n, m % n < m0, m % n + 1 < (m + 1) % n ⊦ n = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m +1 = m + 1; (s)% ⊦ m < n → n ≠ 0; (s)%trans: ⊦ n < n0 ∧ n0 < n1 → n < n1; (forward) from specification nat-basic%trans-01: ⊦ n < n0 ∧ n0 < n1 → n +1 < n1; (forward) from specification nat-basic%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic