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Proof step 2 from proof modex (previous step)

⊦ m % n = 0 ↔ (∃ n0. m = n0 * n), n = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m % n = 0 ⊦ n = 0, ∃ n0. m = n0 * n

Rule argument

Additional information

Used simplifier rules: mod-mult-01: n ≠ 0 ⊦ (m * n) % n = 0;%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult