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Proof step 7 from proof mult (previous step)

∀ n0, n. (n0 + m0 * n) / n = n0 / n + m0 ∨ n = 0 ⊦ (n0 + n * m0) / n = n0 / n + m0, n = 0

Heuristic quantifier closing applied rule all left

And closed the goal!

Rule argument

pos: left 1 terms: n0, n

Additional information

Used simplifier rules: mult-c: ⊦ m * n = n * m; from specification nat-mult Used terms: n0, n