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Proof step 11 from proof square-interval (previous step)

(m * (m + 1)) % 2 = 0, (n * (n + 1)) % 2 = 0, (n * (n + 1)) / 2 + n0 < ((m + 1) * (m + 2)) / 2, m * (m + 1) ≤ n * (n + 1) + 2 * n0, (m * (m + 1)) / 2 ≤ (n * (n + 1)) / 2 + n0, n0 ≤ n ⊦ 2 = 0, m = n, m * (m + 1) ≤ n * (n + 1) + 2 * n0 ∧ n * (n + 1) + 2 * n0 < (m + 1) * (m + 2)

User applied rule case distinction

And obtained the following new goals

Rule argument

pos: right 3

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