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Proof step 1 from proof square-ls-03 (conclusion)

⊦ m0 ≤ m ∧ m ≤ n → (m * (m + 1)) / 2 + m0 < ((n + 1) * (n + 2)) / 2

System applied rule normalize

And obtained the following new goals

Proof step 2:
m0 ≤ m, m ≤ n ⊦ (m * (m + 1)) / 2 + m0 < ((n + 1) * (n + 2)) / 2

Rule argument

Additional information