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Proof step 12 from proof square-ls-03 (previous step)

(m * (m + 1) + 2 * m0) / 2 < ((m + 1) * (m + 2)) / 2, ((m + 1) * (m + 2)) / 2 ≤ ((n + 1) * (n + 2)) / 2, m ≤ n, m0 ≤ m ⊦ n < m, (m * (m + 1) + 2 * m0) / 2 < ((n + 1) * (n + 2)) / 2, (m * (m + 1) + 2 * m0) / 2 < ((m + 1) * (m + 2)) / 2 ∧ ((m + 1) * (m + 2)) / 2 ≤ ((n + 1) * (n + 2)) / 2

User applied rule case distinction

And closed the goal!

Rule argument

pos: right 3

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