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Proof step 2 from proof two-le-02 (previous step)

m % 2 = 0, n % 2 = 0 ⊦ m / 2 ≤ n / 2 ↔ m ≤ n

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: two-le-03: ⊦ m % 2 = 0 → (m / 2 ≤ n ↔ m ≤ n * 2);%mult-02: n ≠ 0 ⊦ m % n = 0 → m / n * n = m;%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult