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Proof step 11 from proof two-loup-04 (previous step)

m + n = (2 * m1 + 2) + n0, m + 1 < m1, 2 + m < m1, n < m1, m < n, m + 1 < n, n0 < 2, m < m1 ⊦ m + 1 = n, m + n < 2 * m1

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
m + n = (2 * m1 + 2) + n0, m < m1, n0 < 2, m + 1 < n, m < n, n < m1, 2 + m < m1, m + 1 < m1, 2 * m1 ≤ m + n ⊦ m + 1 = n

Rule argument

Additional information

Used simplifier rules: ⊦ m < n ↔ ¬ n ≤ m; (ss)