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Proof step 5 from proof two-neq-02 (previous step)

m = m0 * 2 + n0, m0 = m + n + 1, n0 < 2 ⊦ 2 = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 6:
m = (2 * (m + n) + 2) + n0, n0 < 2 ⊦

Rule argument

Additional information

Used simplifier rules: f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m * (n + 1) = m * n + m; (s)