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Proof step 2 from proof two-zero-01-01 (previous step)

⊦ m / 2 = 0 ↔ m = 0 ∨ m = 1

Heuristic elimination applied rule insert elim lemma

And obtained the following new goals

Proof step 3:
n ≠ 0 ⊦ m0 = m / n ∧ n0 = m % n ↔ m = m0 * n + n0 ∧ n0 < n
Proof step 4:
m = m0 * 2 + n0, n0 < 2 ⊦ m0 = 0 ↔ m = 0 ∨ m = 1, 2 = 0

Rule argument

spec: <toplevel> name: div-elim seq: n ≠ 0 ⊦ m0 = m / n ∧ n0 = m % n ↔ m = m0 * n + n0 ∧ n0 < n subst: [m, n, m0, n0] → [m, 2, m0, n] flags: <rotated> <all paths>

Additional information

Used terms: m, 2, m0, n