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Proof step 13 from proof max-a (previous step)

max(m, n) < m, n0 < m, n < m, n < n0, max(m, n) < n0, n + 1 < m, max(m, n) + 1 < m ⊦ m = n0

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: m < n

Additional information

Used simplifier rules: Max-right: ⊦ ¬ m < n → max(m, n) = m;% ⊦ ¬ n < n; (s)% ⊦ m < n → ¬ n < m; (s) Used formulas: m < n