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Proof step 7 from proof max-a (previous step)

m < max(m, n), n0 < max(m, n), n < n0, m < n0, n + 1 < max(m, n), n < max(m, n), m + 1 < max(m, n) ⊦ n0 = max(m, n)

Heuristic weak cut applied rule cut formula

And closed the goal!

Rule argument

fma: m < n

Additional information

Used simplifier rules: Max-left: ⊦ m < n → max(m, n) = n;%Max-right: ⊦ ¬ m < n → max(m, n) = m;% ⊦ ¬ n < n; (s)% ⊦ m < n → ¬ n < m; (s) Used formulas: m < n