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Proof step 2 from proof odd-div2 (previous step)

odd(n) ⊦ (n + 1) / 2 = n / 2 + 1

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: oex: ⊦ odd(n) ↔ (∃ m. n = m + m + 1);% ⊦ m + n = m + n0 ↔ n = n0; (s)% ⊦ (2 * m + 1) / 2 = m; (s)%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult% ⊦ (2 * m) / 2 = m; (s)% ⊦ (m + 2) / 2 = m / 2 + 1; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + m = 2 * m; (s)