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Proof step 2 from proof plus (previous step)

even(m) ⊦ even(m + n) ↔ even(n)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
2 * m = 2 * m0 + n ⊦ ∃ m0. 2 * m0 = n

Rule argument

Additional information

Used simplifier rules: Even: ⊦ even(n) ↔ (∃ m. m + m = n);%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult% ⊦ m * n + m0 * n = m1 * n ↔ m + m0 = m1 ∨ n = 0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + m = 2 * m; (s)