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Proof step 6 from proof plus (previous step)

2 * m = 2 * m0 + n, 2 * m = 2 * m0 + n → ¬ m < m0 ⊦ 2 * (m - m0) = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Rule argument

Additional information

Used simplifier rules: ⊦ 2 * m = 2 * n + m0 → ¬ m < n; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%mult-c: ⊦ m * n = n * m; from specification nat-mult%mult-a: ⊦ m0 * m * n = (m0 * m) * n; from specification nat-mult