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Proof step 3 from proof pot2-odd-02 (previous step)

n = m0 * 2 + n0, n0 < 2 ⊦ m0 * 2 + 1 = n, 2 = 0, ∃ m. 2 * m = n

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
⊦ ∃ m. 2 * m = m0 * 2

Rule argument

Additional information

Used simplifier rules: ⊦ n + 0 = n; (s)% ⊦ m ≠ 1 → (m < 2 ↔ m = 0); (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m + n = m + n0 ↔ n = n0; (s)