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Proof step 2 from proof add-assoc (previous step)

⊦ (n∞ + n∞1) + ⌜m⌝ = n∞ + n∞1 + ⌜m⌝

User applied rule structural induction

And obtained the following new goals

Proof step 3:
⊦ (∞ + n∞1) + ⌜m⌝ = ∞ + n∞1 + ⌜m⌝
Proof step 9:
⊦ (⌜m0⌝ + n∞1) + ⌜m⌝ = ⌜m0⌝ + n∞1 + ⌜m⌝

Rule argument

indvar: n∞

Additional information

Used simplifier rules: gen: ⊦ ;