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Proof step 11 from proof add-ls-cancel-01 (previous step)

n∞1 < ⌜m⌝ ⊦ ⌜n⌝ + n∞1 < ⌜n⌝ + ⌜m⌝

User applied rule structural induction

And closed the goal!

Rule argument

indvar: n∞1

Additional information

Used simplifier rules: gen: ⊦ ;%less-inf1: ⊦ ¬ ∞ < n∞;%less-fin: ⊦ ⌜m⌝ < ⌜n⌝ ↔ m < n;%ls-natinf-to-nat-2-2: ⊦ ⌜n⌝ + ⌜m⌝ < ⌜n0⌝ + ⌜n1⌝ ↔ n + m < n0 + n1;%add-assoc: ⊦ (n∞ + n∞1) + n∞2 = n∞ + n∞1 + n∞2;%add-comm: ⊦ n∞1 + n∞2 = n∞2 + n∞1;% ⊦ m + n < m + n0 ↔ n < n0; (s)% ⊦ m < n ↔ ¬ n ≤ m; (ss)% ⊦ m < n → (n ≤ m ↔ false); (s)%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic%c: ⊦ m + n = n + m; from specification nat-basic