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Proof step 3 from proof less-less-leftsucc (previous step)

n∞ < n∞0 ⊦ n∞ + ⌜1⌝ = n∞0, n∞ = ∞, n∞ + ⌜1⌝ < n∞0

User applied rule constructor cut

And obtained the following new goals

Proof step 4:
n∞0 = ⌜m⌝ , n∞ < n∞0 ⊦ n∞ + ⌜1⌝ = n∞0, n∞ = ∞, n∞ + ⌜1⌝ < n∞0

Rule argument

var: n∞0

Additional information

Used simplifier rules: gen: ⊦ ;%inf-less: ⊦ n∞ < ∞ ↔ n∞ ≠ ∞;