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Proof step 2 from proof addle-01 (previous step)

m * n1 = m * m0 + n0, n1 < m0 ⊦ m = 0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m * n1 = m * m0 + n0, n1 < m0 ⊦ m = 0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic