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Proof step 3 from proof le-04 (previous step)

m ≤ n ⊦ n * n0 ≤ m ↔ n0 = 0 ∨ n0 = 1 ∧ m = n ∨ n = 0

User applied rule cut formula

And obtained the following new goals

Proof step 4:
m ≤ n ⊦ n * n0 ≤ m ↔ n0 = 0 ∨ n0 = 1 ∧ m = n ∨ n = 0, n0 = 0

Rule argument

fma: n0 = 0

Additional information

Used simplifier rules: mult-base: ⊦ m * 0 = 0;%mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;% ⊦ 0 ≤ m; (s) Used formulas: n0 = 0