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Proof step 2 from proof ls-03-num (previous step)

m ≤ n ⊦ n * n0 < m ↔ n0 = 0, m = 0

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: ls-10: ⊦ m ≤ n ∧ n0 ≠ 0 → ¬ n * n0 < m;%mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;%mult-base: ⊦ m * 0 = 0;% ⊦ 0 < n ↔ n ≠ 0; (s)