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Proof step 2 from proof mod-ls (previous step)

m0 < m, n2 < n0, n1 < n, n ≤ n0 ⊦ m0 * n + n1 < m * n0 + n2

Heuristic simplifier applied rule simplifier

And closed the goal!

Rule argument

Additional information

Used simplifier rules: modls-01: ⊦ n ≤ n0 ∧ n2 < n0 ∧ m1 < m ∧ n1 < n → m1 * n + n1 < m * n0 + n2;%mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic