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Proof step 2 from proof modls-03 (previous step)

n2 < n, m1 < m, n1 < n ⊦ m1 * n + n1 < m * n + n2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
n2 < n, m1 < m, n1 < n, m * n + n2 ≤ m1 * n + n1 ⊦

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m < n ↔ ¬ n ≤ m; (ss)