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Proof step 11 from proof modls (previous step)

m < n, n0 < m0, m0 * n ≤ m0 * m + n0 ⊦ m0 * n = m0 * m + n0

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 12:
m0 * n < m0 * m + n0, m < n, n0 < m0 ⊦ m0 * n = m0 * m + n0

Rule argument

Additional information

Used simplifier rules: ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic% ⊦ m ≠ n → (m ≤ n ↔ m < n); (s)