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Proof step 4 from proof modp (previous step)

n0 < m0, m1 + 1 < n, m0 * n ≤ (m1 * m0 + m0) + n0, ∀ n1, n2, m. ¬ m1 < n1 ∨ ¬ n2 < m ∨ ¬ m * n1 ≤ m * m1 + n2 ⊦

User applied rule all left

And obtained the following new goals

Proof step 5:
m1 + 1 < n, n0 < m0, m0 * n ≤ (m1 * m0 + m0) + n0, ¬ m1 < n -1 ∨ ¬ n0 < m0 ∨ ¬ m0 * n -1 ≤ m0 * m1 + n0 ⊦

Rule argument

pos: left 4 terms: n -1, n0, m0 abort: F discard: T computed: F

Additional information

Used terms: n -1, n0, m0