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Proof step 1 from proof mult-eq-succ-02 (conclusion)

⊦ m1 + 1 = m1 * m0 ↔ m1 = 1 ∧ m0 = 2

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 2:
m1 + 1 = m1 * m0 ⊦ m1 = 1 ∧ m0 = 2

Rule argument

Additional information

Used simplifier rules: mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;