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Proof step 3 from proof mult-eq-succ (previous step)

m + 1 = m1 * m0, m < m1, m1 * m0 ≤ m1 ⊦ m0 = 1

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ m1 * m0 ≤ m1 ↔ m1 = 0 ∨ m0 ≤ 1
Proof step 5:
m + 1 = m1 * m0, m < m1, m1 = 0 ∨ m0 ≤ 1 ⊦ m0 = 1

Rule argument

spec: <toplevel> name: mult-le seq: ⊦ m1 * m0 ≤ m1 ↔ m1 = 0 ∨ m0 ≤ 1 subst: [m0, m1] → [m0, m1] flags: <all paths>

Additional information

Used terms: m0, m1