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Proof step 2 from proof numeral-17 (previous step)

m2 * m + n < m1 * m, m1 < m2 ⊦

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 3:
m2 * m + n < m1 * m, m1 < m2 ⊦ m = 0, m1 = 0

Rule argument

Additional information

Used simplifier rules: zero-01: ⊦ m0 * m = 0 ↔ m0 = 0 ∨ m = 0;%mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;% ⊦ m < n → n ≠ 0; (s)%f: ⊦ m < n → n ≠ 0; (forward) from specification nat-basic