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Proof step 5 from proof numeral-17 (previous step)

(m * m0 + m) + n < m1 * m, m1 ≤ m0, ∀ m, n, m1. m0 * m + n < m1 * m ∧ m1 < m0 → m = 0 ∨ m1 = 0 ⊦ m = 0, m1 = 0

User applied rule constructor cut

And obtained the following new goals

Proof step 6:
m1 = m2 +1, (m * m0 + m) + n < m1 * m, m1 ≤ m0, ∀ m, n, m1. m0 * m + n < m1 * m ∧ m1 < m0 → m = 0 ∨ m1 = 0 ⊦ m = 0, m1 = 0

Rule argument

var: m1

Additional information

Used simplifier rules: nat freely generated by 0, +1;;