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Proof step 3 from proof rdist (previous step)

∀ m0, m. m0 * m + m0 * n0 = m0 * (m + n0) ⊦ m0 * m + m0 * n0 +1 = m0 * (m + n0 +1)

Heuristic simplifier applied rule simplifier

And obtained the following new goals

Proof step 4:
∀ m0, m. m0 * m + m0 * n0 = m0 * (m + n0) ⊦ m0 * m + m0 * n0 = m0 * (m + n0)

Rule argument

Additional information

Used simplifier rules: rsucc-02: ⊦ m * (n + 1) = m * n + m;% ⊦ m + n = m + n0 ↔ n = n0; (s)%c: ⊦ m + n = n + m; from specification nat-basic%a: ⊦ (m + n0) + n1 = m + n0 + n1; from specification nat-basic% ⊦ m +1 = m + 1; (s)