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Proof step 3 from proof square-even (previous step)

m * m + m = 2 * n + 1 ⊦

User applied rule apply lemma

And obtained the following new goals

Proof step 4:
⊦ (∃ n. m = 2 * n) ∨ (∃ n. m = 2 * n + 1)
Proof step 5:
m * m + m = 2 * n + 1, (∃ n. m = 2 * n) ∨ (∃ n. m = 2 * n + 1) ⊦

Rule argument

spec: <toplevel> name: ex-two seq: ⊦ (∃ n. m = 2 * n) ∨ (∃ n. m = 2 * n + 1) subst: [m] → [m]

Additional information

Used terms: m