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Proof step 6 from proof square-even (
previous step
)
m * m + m = 2 * n + 1, m = 2 * n0 ∨ m = 2 * n1 + 1 ⊦
User applied rule case distinction
And obtained the following new goals
Proof step 7
:
m * m + m = 2 * n + 1, m = 2 * n0 ⊦
Proof step 10
:
m * m + m = 2 * n + 1, m = 2 * n1 + 1 ⊦
Rule argument
pos: left 2
Additional information