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Proof step 1 from proof square-inject (conclusion)

m * (m + 1) + 2 * m0 = n * (n + 1) + 2 * n0, m0 ≤ m, n0 ≤ n ⊦ m = n ∧ m0 = n0

System applied rule normalize

And obtained the following new goals

Proof step 2:
m * (m + 1) + 2 * m0 = n * (n + 1) + 2 * n0, n0 ≤ n, m0 ≤ m ⊦ m = n ∧ m0 = n0

Rule argument

Additional information