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Proof step 3 from proof square-le-03 (previous step)

⊦ ¬ n * (n + m0) < m * (m + m0) ↔ m ≤ n

User applied rule insert rewrite lemma

And obtained the following new goals

Proof step 4:
⊦ m * (m + m0) < n * (n + m0) ↔ m < n
Proof step 5:
⊦ ¬ n < m ↔ m ≤ n

Rule argument

spec: <toplevel> name: square-ls-05 seq: ⊦ m * (m + m0) < n * (n + m0) ↔ m < n subst: [n, m0, m] → [m, m0, n] flags: <all paths>

Additional information

Used terms: m, m0, n