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Proof step 9 from proof square-two (previous step)

n * n + n = m * 2, m ≤ n, n = 1 ∨ n = 0 ⊦ n = m ∧ m < 2

User applied rule case distinction

And closed the goal!

Rule argument

pos: left 3

Additional information

Used simplifier rules: mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;%twoeq: ⊦ 2 = 2 * n ↔ n = 1;%mult-a: ⊦ m0 * m * n = (m0 * m) * n;%mult-c: ⊦ m * n = n * m;%two-zero-01: ⊦ 2 * m = 0 ↔ m = 0;% ⊦ m ≤ 0 ↔ m = 0; (s)